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1300130221981 is a prime number
BaseRepresentation
bin10010111010110101110…
…011001100111110011101
311121021212022101102012111
4102322311303030332131
5132300131314100411
62433134354434021
7162634303355323
oct22726563147635
94537768342174
101300130221981
11461422685968
1218bb82b92911
13957a908cc76
1446cd89a5d13
1523c45599721
hex12eb5cccf9d

1300130221981 has 2 divisors, whose sum is σ = 1300130221982. Its totient is φ = 1300130221980.

The previous prime is 1300130221937. The next prime is 1300130222023. The reversal of 1300130221981 is 1891220310031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 879103136025 + 421027085956 = 937605^2 + 648866^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300130221981 - 231 = 1297982738333 is a prime.

It is a super-2 number, since 2×13001302219812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300130222981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650065110990 + 650065110991.

It is an arithmetic number, because the mean of its divisors is an integer number (650065110991).

Almost surely, 21300130221981 is an apocalyptic number.

It is an amenable number.

1300130221981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300130221981 is an equidigital number, since it uses as much as digits as its factorization.

1300130221981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 1300130221981 in words is "one trillion, three hundred billion, one hundred thirty million, two hundred twenty-one thousand, nine hundred eighty-one".