130013101310031 has 12 divisors (see below), whose sum is σ = 193854660018240. Its totient is φ = 83879420199840.

The previous prime is 130013101310021. The next prime is 130013101310041.

130013101310031 is a `hidden beast` number, since 1 + 300 + 1 + 310 + 13 + 10 + 0 + 31 = 666.

130013101310031 is nontrivially palindromic in base 10.

It is an interprime number because it is at equal distance from previous prime (130013101310021) and next prime (130013101310041).

It is not a de Polignac number, because 130013101310031 - 2⁵ = 130013101309999 is a prime.

It is a super-2 number, since 2×130013101310031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130013101309986 and 130013101310013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130013101310021) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 232998389166 + ... + 232998389723.

It is an arithmetic number, because the mean of its divisors is an integer number (16154555001520).

Almost surely, 2^{130013101310031} is an apocalyptic number.

130013101310031 is a deficient number, since it is larger than the sum of its proper divisors (63841558708209).

130013101310031 is a wasteful number, since it uses less digits than its factorization.

130013101310031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465996778926 (or 465996778923 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

It can be divided in two parts, 13001310 and 1310031, that added together give a palindrome (14311341).

The spelling of 130013101310031 in words is "one hundred thirty trillion, thirteen billion, one hundred one million, three hundred ten thousand, thirty-one".