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13001314141 = 24247536203
BaseRepresentation
bin11000001101111000…
…00100111101011101
31020120002021012010101
430012330010331131
5203111314023031
65550035141101
7640120226644
oct140674047535
936502235111
1013001314141
1155719a2822
12262a144791
1312c2741bba
148b49cc35b
15511611361
hex306f04f5d

13001314141 has 4 divisors (see below), whose sum is σ = 13001874592. Its totient is φ = 13000753692.

The previous prime is 13001314057. The next prime is 13001314189. The reversal of 13001314141 is 14141310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14141310031 = 33614207471.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13001314141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001314541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243855 + ... + 292348.

It is an arithmetic number, because the mean of its divisors is an integer number (3250468648).

Almost surely, 213001314141 is an apocalyptic number.

It is an amenable number.

13001314141 is a deficient number, since it is larger than the sum of its proper divisors (560451).

13001314141 is an equidigital number, since it uses as much as digits as its factorization.

13001314141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 560450.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13001314141 its reverse (14141310031), we get a palindrome (27142624172).

The spelling of 13001314141 in words is "thirteen billion, one million, three hundred fourteen thousand, one hundred forty-one".

Divisors: 1 24247 536203 13001314141