1300133431141 has 4 divisors (see below), whose sum is σ = 1300175198784. Its totient is φ = 1300091663500.

The previous prime is 1300133431067. The next prime is 1300133431151. The reversal of 1300133431141 is 1411343310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300133431141 - 2¹¹ = 1300133429093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300133431151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20837095 + ... + 20899396.

It is an arithmetic number, because the mean of its divisors is an integer number (325043799696).

Almost surely, 2^{1300133431141} is an apocalyptic number.

It is an amenable number.

1300133431141 is a deficient number, since it is larger than the sum of its proper divisors (41767643).

1300133431141 is an equidigital number, since it uses as much as digits as its factorization.

1300133431141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41767642.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1300133431141 its reverse (1411343310031), we get a palindrome (2711476741172).

The spelling of 1300133431141 in words is "one trillion, three hundred billion, one hundred thirty-three million, four hundred thirty-one thousand, one hundred forty-one".