Base | Representation |
---|---|
bin | 1011110100110001101111… |
… | …1010110010100011011011 |
3 | 1201000220201100102010122202 |
4 | 2331030123322302203123 |
5 | 3201003213101314433 |
6 | 43352421445240415 |
7 | 2511213121001126 |
oct | 275143372624333 |
9 | 51026640363582 |
10 | 13001334401243 |
11 | 4162920364141 |
12 | 155b8b470310b |
13 | 734036279756 |
14 | 32d3a733d3bd |
15 | 1782db8beee8 |
hex | bd31beb28db |
13001334401243 has 4 divisors (see below), whose sum is σ = 13184451787248. Its totient is φ = 12818217015240.
The previous prime is 13001334401207. The next prime is 13001334401249. The reversal of 13001334401243 is 34210443310031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13001334401243 - 212 = 13001334397147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13001334401249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91558692896 + ... + 91558693037.
It is an arithmetic number, because the mean of its divisors is an integer number (3296112946812).
Almost surely, 213001334401243 is an apocalyptic number.
13001334401243 is a deficient number, since it is larger than the sum of its proper divisors (183117386005).
13001334401243 is an equidigital number, since it uses as much as digits as its factorization.
13001334401243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183117386004.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13001334401243 its reverse (34210443310031), we get a palindrome (47211777711274).
The spelling of 13001334401243 in words is "thirteen trillion, one billion, three hundred thirty-four million, four hundred one thousand, two hundred forty-three".
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