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130014019 is a prime number
BaseRepresentation
bin1111011111111…
…01101101000011
3100001122101201001
413233331231003
5231240422034
620522352431
73136046422
oct757755503
9301571631
10130014019
1167431503
123765b717
1320c21c95
14133a52b9
15b632a14
hex7bfdb43

130014019 has 2 divisors, whose sum is σ = 130014020. Its totient is φ = 130014018.

The previous prime is 130013981. The next prime is 130014037. The reversal of 130014019 is 910410031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130014019 is a prime.

It is a super-2 number, since 2×1300140192 = 33807290273064722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130013987 and 130014005.

It is not a weakly prime, because it can be changed into another prime (130012019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007009 + 65007010.

It is an arithmetic number, because the mean of its divisors is an integer number (65007010).

Almost surely, 2130014019 is an apocalyptic number.

130014019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014019 is an equidigital number, since it uses as much as digits as its factorization.

130014019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

The square root of 130014019 is about 11402.3690082368. The cubic root of 130014019 is about 506.5979108475.

It can be divided in two parts, 13001 and 4019, that added together give a triangular number (17020 = T184).

The spelling of 130014019 in words is "one hundred thirty million, fourteen thousand, nineteen".