13001403141201 has 4 divisors (see below), whose sum is σ = 17335204188272. Its totient is φ = 8667602094132.

The previous prime is 13001403141191. The next prime is 13001403141227. The reversal of 13001403141201 is 10214130410031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13001403141201 - 2²⁵ = 13001369586769 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13001403141101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166900523531 + ... + 2166900523536.

It is an arithmetic number, because the mean of its divisors is an integer number (4333801047068).

Almost surely, 2^{13001403141201} is an apocalyptic number.

It is an amenable number.

13001403141201 is a deficient number, since it is larger than the sum of its proper divisors (4333801047071).

13001403141201 is an equidigital number, since it uses as much as digits as its factorization.

13001403141201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4333801047070.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13001403141201 its reverse (10214130410031), we get a palindrome (23215533551232).

The spelling of 13001403141201 in words is "thirteen trillion, one billion, four hundred three million, one hundred forty-one thousand, two hundred one".