1300141004321 has 4 divisors (see below), whose sum is σ = 1310065744944. Its totient is φ = 1290216263700.

The previous prime is 1300141004231. The next prime is 1300141004341. The reversal of 1300141004321 is 1234001410031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300141004321 - 2¹⁰ = 1300141003297 is a prime.

It is a super-2 number, since 2×1300141004321² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300141004293 and 1300141004302.

It is not an unprimeable number, because it can be changed into a prime (1300141004341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4962370115 + ... + 4962370376.

It is an arithmetic number, because the mean of its divisors is an integer number (327516436236).

Almost surely, 2^{1300141004321} is an apocalyptic number.

It is an amenable number.

1300141004321 is a deficient number, since it is larger than the sum of its proper divisors (9924740623).

1300141004321 is an equidigital number, since it uses as much as digits as its factorization.

1300141004321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9924740622.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1300141004321 its reverse (1234001410031), we get a palindrome (2534142414352).

The spelling of 1300141004321 in words is "one trillion, three hundred billion, one hundred forty-one million, four thousand, three hundred twenty-one".