Search a number
-
+
13001421412114 = 26500710706057
BaseRepresentation
bin1011110100110010000100…
…0110101101011100010010
31201000220221102010202010121
42331030201012231130102
53201003402340141424
643352434234220454
72511215225404132
oct275144106553422
951026842122117
1013001421412114
114162965493753
12155b91988472a
1373404b2c2c85
1432d3b4b0cac2
151782e435aee4
hexbd3211ad712

13001421412114 has 4 divisors (see below), whose sum is σ = 19502132118174. Its totient is φ = 6500710706056.

The previous prime is 13001421412081. The next prime is 13001421412121. The reversal of 13001421412114 is 41121412410031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11366304246025 + 1635117166089 = 3371395^2 + 1278717^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250355353027 + ... + 3250355353030.

Almost surely, 213001421412114 is an apocalyptic number.

13001421412114 is a deficient number, since it is larger than the sum of its proper divisors (6500710706060).

13001421412114 is an equidigital number, since it uses as much as digits as its factorization.

13001421412114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6500710706059.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 13001421412114 its reverse (41121412410031), we get a palindrome (54122833822145).

The spelling of 13001421412114 in words is "thirteen trillion, one billion, four hundred twenty-one million, four hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 6500710706057 13001421412114