41121412410031 has 4 divisors (see below), whose sum is σ = 41121468076912. Its totient is φ = 41121356743152.

The previous prime is 41121412410011. The next prime is 41121412410083. The reversal of 41121412410031 is 13001421412114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41121412410031 - 2⁵ = 41121412409999 is a prime.

It is a super-2 number, since 2×41121412410031² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41121412409978 and 41121412410005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41121412410011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26710275 + ... + 28207828.

It is an arithmetic number, because the mean of its divisors is an integer number (10280367019228).

Almost surely, 2^{41121412410031} is an apocalyptic number.

41121412410031 is a deficient number, since it is larger than the sum of its proper divisors (55666881).

41121412410031 is an equidigital number, since it uses as much as digits as its factorization.

41121412410031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55666880.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 41121412410031 its reverse (13001421412114), we get a palindrome (54122833822145).

The spelling of 41121412410031 in words is "forty-one trillion, one hundred twenty-one billion, four hundred twelve million, four hundred ten thousand, thirty-one".