Search a number
-
+
1300143122 = 2650071561
BaseRepresentation
bin100110101111110…
…1001110000010010
310100121110010001222
41031133221300102
510130314034442
6333002325042
744135014505
oct11537516022
93317403058
101300143122
11607995853
123034b9782
13179488175
14c495b13c
157921c8d2
hex4d7e9c12

1300143122 has 4 divisors (see below), whose sum is σ = 1950214686. Its totient is φ = 650071560.

The previous prime is 1300143121. The next prime is 1300143151. The reversal of 1300143122 is 2213410031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 2213410031 = 7316201433.

It can be written as a sum of positive squares in only one way, i.e., 1174501441 + 125641681 = 34271^2 + 11209^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1300143122.

It is not an unprimeable number, because it can be changed into a prime (1300143121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325035779 + ... + 325035782.

Almost surely, 21300143122 is an apocalyptic number.

1300143122 is a deficient number, since it is larger than the sum of its proper divisors (650071564).

1300143122 is an equidigital number, since it uses as much as digits as its factorization.

1300143122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 650071563.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1300143122 is about 36057.4974450529. The cubic root of 1300143122 is about 1091.4329334714.

Adding to 1300143122 its reverse (2213410031), we get a palindrome (3513553153).

The spelling of 1300143122 in words is "one billion, three hundred million, one hundred forty-three thousand, one hundred twenty-two".

Divisors: 1 2 650071561 1300143122