Search a number
-
+
1300143401 is a prime number
BaseRepresentation
bin100110101111110…
…1001110100101001
310100121110010110022
41031133221310221
510130314042101
6333002330225
744135015354
oct11537516451
93317403408
101300143401
11607995a87
123034b9975
1317948832b
14c495b29b
157921ca1b
hex4d7e9d29

1300143401 has 2 divisors, whose sum is σ = 1300143402. Its totient is φ = 1300143400.

The previous prime is 1300143373. The next prime is 1300143421. The reversal of 1300143401 is 1043410031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1113957376 + 186186025 = 33376^2 + 13645^2 .

It is an emirp because it is prime and its reverse (1043410031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300143401 - 26 = 1300143337 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300143401.

It is not a weakly prime, because it can be changed into another prime (1300143421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650071700 + 650071701.

It is an arithmetic number, because the mean of its divisors is an integer number (650071701).

Almost surely, 21300143401 is an apocalyptic number.

It is an amenable number.

1300143401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300143401 is an equidigital number, since it uses as much as digits as its factorization.

1300143401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1300143401 is about 36057.5013138737. The cubic root of 1300143401 is about 1091.4330115423.

Adding to 1300143401 its reverse (1043410031), we get a palindrome (2343553432).

The spelling of 1300143401 in words is "one billion, three hundred million, one hundred forty-three thousand, four hundred one".