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1300143411401 = 10335593546713
BaseRepresentation
bin10010111010110110100…
…101100001000011001001
311121021220020012111200112
4102322312211201003021
5132300143203131101
62433135545244105
7162634523440412
oct22726645410311
94537806174615
101300143411401
1146142a07430a
1218bb87493635
13957aba2a463
1446cda63a809
1523c468026bb
hex12eb69610c9

1300143411401 has 8 divisors (see below), whose sum is σ = 1313135391360. Its totient is φ = 1287158532192.

The previous prime is 1300143411367. The next prime is 1300143411431. The reversal of 1300143411401 is 1041143410031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300143411401 - 230 = 1299069669577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300143411431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1406780 + ... + 2139933.

It is an arithmetic number, because the mean of its divisors is an integer number (164141923920).

Almost surely, 21300143411401 is an apocalyptic number.

It is an amenable number.

1300143411401 is a deficient number, since it is larger than the sum of its proper divisors (12991979959).

1300143411401 is a wasteful number, since it uses less digits than its factorization.

1300143411401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3550375.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1300143411401 its reverse (1041143410031), we get a palindrome (2341286821432).

The spelling of 1300143411401 in words is "one trillion, three hundred billion, one hundred forty-three million, four hundred eleven thousand, four hundred one".

Divisors: 1 103 3559 366577 3546713 365311439 12622751567 1300143411401