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1300144019 is a prime number
BaseRepresentation
bin100110101111110…
…1001111110010011
310100121110011022012
41031133221332103
510130314102034
6333002333135
744135020226
oct11537517623
93317404265
101300144019
11607996499
123034ba1ab
131794886b5
14c495b5bd
157921ccce
hex4d7e9f93

1300144019 has 2 divisors, whose sum is σ = 1300144020. Its totient is φ = 1300144018.

The previous prime is 1300143997. The next prime is 1300144031. The reversal of 1300144019 is 9104410031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300144019 - 28 = 1300143763 is a prime.

It is a super-2 number, since 2×13001440192 = 3380748940282944722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300143985 and 1300144003.

It is not a weakly prime, because it can be changed into another prime (1300144099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650072009 + 650072010.

It is an arithmetic number, because the mean of its divisors is an integer number (650072010).

Almost surely, 21300144019 is an apocalyptic number.

1300144019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300144019 is an equidigital number, since it uses as much as digits as its factorization.

1300144019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The square root of 1300144019 is about 36057.5098835180. The cubic root of 1300144019 is about 1091.4331844733.

The spelling of 1300144019 in words is "one billion, three hundred million, one hundred forty-four thousand, nineteen".