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1300144311353 = 9348113908113
BaseRepresentation
bin10010111010110110101…
…000111100110000111001
311121021220021220020012002
4102322312220330300321
5132300143420430403
62433140020430345
7162634534206236
oct22726650746071
94537807806162
101300144311353
1146142a629478
1218bb878483b5
13957abc83c84
1446cda7d278d
1523c4692e188
hex12eb6a3cc39

1300144311353 has 4 divisors (see below), whose sum is σ = 1300158312948. Its totient is φ = 1300130309760.

The previous prime is 1300144311341. The next prime is 1300144311377. The reversal of 1300144311353 is 3531134410031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 608332921849 + 691811389504 = 779957^2 + 831752^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300144311353 - 216 = 1300144245817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300144311853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6860576 + ... + 7047537.

It is an arithmetic number, because the mean of its divisors is an integer number (325039578237).

Almost surely, 21300144311353 is an apocalyptic number.

It is an amenable number.

1300144311353 is a deficient number, since it is larger than the sum of its proper divisors (14001595).

1300144311353 is an equidigital number, since it uses as much as digits as its factorization.

1300144311353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14001594.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1300144311353 its reverse (3531134410031), we get a palindrome (4831278721384).

The spelling of 1300144311353 in words is "one trillion, three hundred billion, one hundred forty-four million, three hundred eleven thousand, three hundred fifty-three".

Divisors: 1 93481 13908113 1300144311353