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13001444131241 = 61499427131119
BaseRepresentation
bin1011110100110010001001…
…1101011000000110101001
31201000220222222212222220202
42331030202131120012221
53201003424144144431
643352440405201545
72511215622456506
oct275144235300651
951026888788822
1013001444131241
1141629772a0995
12155b9254002b5
13734052c18c47
1432d3b7b444ad
151782e63478cb
hexbd3227581a9

13001444131241 has 8 divisors (see below), whose sum is σ = 13241064720000. Its totient is φ = 12762677805840.

The previous prime is 13001444131229. The next prime is 13001444131279. The reversal of 13001444131241 is 14213144410031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13001444131241 - 218 = 13001443869097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001444131211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213535121 + ... + 213595998.

It is an arithmetic number, because the mean of its divisors is an integer number (1655133090000).

Almost surely, 213001444131241 is an apocalyptic number.

It is an amenable number.

13001444131241 is a deficient number, since it is larger than the sum of its proper divisors (239620588759).

13001444131241 is an equidigital number, since it uses as much as digits as its factorization.

13001444131241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 427131679.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 13001444131241 its reverse (14213144410031), we get a palindrome (27214588541272).

The spelling of 13001444131241 in words is "thirteen trillion, one billion, four hundred forty-four million, one hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 61 499 30439 427131119 26054998259 213138428381 13001444131241