Base | Representation |
---|---|
bin | 1011110100110010001011… |
… | …0111111101100110000001 |
3 | 1201000221000111000002000010 |
4 | 2331030202313331212001 |
5 | 3201003432440204140 |
6 | 43352441214415133 |
7 | 2511216035634255 |
oct | 275144267754601 |
9 | 51027014002003 |
10 | 13001451100545 |
11 | 4162980221046 |
12 | 155b9278014a9 |
13 | 7340544b91ab |
14 | 32d3b8a3a265 |
15 | 1782e6c72880 |
hex | bd322dfd981 |
13001451100545 has 16 divisors (see below), whose sum is σ = 21364546674240. Its totient is φ = 6746698949184.
The previous prime is 13001451100459. The next prime is 13001451100571. The reversal of 13001451100545 is 54500115410031.
It is not a de Polignac number, because 13001451100545 - 221 = 13001449003393 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11713018455 + ... + 11713019564.
It is an arithmetic number, because the mean of its divisors is an integer number (1335284167140).
Almost surely, 213001451100545 is an apocalyptic number.
13001451100545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13001451100545 is a deficient number, since it is larger than the sum of its proper divisors (8363095573695).
13001451100545 is a wasteful number, since it uses less digits than its factorization.
13001451100545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23426038064.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 13001451100545 its reverse (54500115410031), we get a palindrome (67501566510576).
The spelling of 13001451100545 in words is "thirteen trillion, one billion, four hundred fifty-one million, one hundred thousand, five hundred forty-five".
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