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13001451100545 = 353723426038019
BaseRepresentation
bin1011110100110010001011…
…0111111101100110000001
31201000221000111000002000010
42331030202313331212001
53201003432440204140
643352441214415133
72511216035634255
oct275144267754601
951027014002003
1013001451100545
114162980221046
12155b9278014a9
137340544b91ab
1432d3b8a3a265
151782e6c72880
hexbd322dfd981

13001451100545 has 16 divisors (see below), whose sum is σ = 21364546674240. Its totient is φ = 6746698949184.

The previous prime is 13001451100459. The next prime is 13001451100571. The reversal of 13001451100545 is 54500115410031.

It is not a de Polignac number, because 13001451100545 - 221 = 13001449003393 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11713018455 + ... + 11713019564.

It is an arithmetic number, because the mean of its divisors is an integer number (1335284167140).

Almost surely, 213001451100545 is an apocalyptic number.

13001451100545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13001451100545 is a deficient number, since it is larger than the sum of its proper divisors (8363095573695).

13001451100545 is a wasteful number, since it uses less digits than its factorization.

13001451100545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23426038064.

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 13001451100545 its reverse (54500115410031), we get a palindrome (67501566510576).

The spelling of 13001451100545 in words is "thirteen trillion, one billion, four hundred fifty-one million, one hundred thousand, five hundred forty-five".

Divisors: 1 3 5 15 37 111 185 555 23426038019 70278114057 117130190095 351390570285 866763406703 2600290220109 4333817033515 13001451100545