Base | Representation |
---|---|
bin | 11101100100000010101111… |
… | …110111000110000100100111 |
3 | 122001100210212022200222011002 |
4 | 131210002233313012010213 |
5 | 114020222332303040403 |
6 | 1140310242215303515 |
7 | 36246435526465031 |
oct | 3544025767060447 |
9 | 561323768628132 |
10 | 130020200440103 |
11 | 3847929158a926 |
12 | 126ba95207ab9b |
13 | 5771b1063c51c |
14 | 2417022d3cc51 |
15 | 10071ccc09188 |
hex | 7640afdc6127 |
130020200440103 has 4 divisors (see below), whose sum is σ = 130020886321560. Its totient is φ = 130019514558648.
The previous prime is 130020200440099. The next prime is 130020200440111. The reversal of 130020200440103 is 301044002020031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130020200440103 - 22 = 130020200440099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130020200440153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342656300 + ... + 343035537.
It is an arithmetic number, because the mean of its divisors is an integer number (32505221580390).
Almost surely, 2130020200440103 is an apocalyptic number.
130020200440103 is a deficient number, since it is larger than the sum of its proper divisors (685881457).
130020200440103 is an equidigital number, since it uses as much as digits as its factorization.
130020200440103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 685881456.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 130020200440103 its reverse (301044002020031), we get a palindrome (431064202460134).
The spelling of 130020200440103 in words is "one hundred thirty trillion, twenty billion, two hundred million, four hundred forty thousand, one hundred three".
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