Base | Representation |
---|---|
bin | 1011110100110100010011… |
… | …0011000001110001101101 |
3 | 1201000222111010220222000001 |
4 | 2331031010303001301231 |
5 | 3201011114134413201 |
6 | 43353013505104301 |
7 | 2511236116320442 |
oct | 275150463016155 |
9 | 51028433828001 |
10 | 13002020232301 |
11 | 4163142506171 |
12 | 155ba66328091 |
13 | 734115397849 |
14 | 32d4304699c9 |
15 | 17832bbe4301 |
hex | bd344cc1c6d |
13002020232301 has 2 divisors, whose sum is σ = 13002020232302. Its totient is φ = 13002020232300.
The previous prime is 13002020232217. The next prime is 13002020232307. The reversal of 13002020232301 is 10323202020031.
13002020232301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9493479160201 + 3508541072100 = 3081149^2 + 1873110^2 .
It is a cyclic number.
It is not a de Polignac number, because 13002020232301 - 221 = 13002018135149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002020232307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501010116150 + 6501010116151.
It is an arithmetic number, because the mean of its divisors is an integer number (6501010116151).
Almost surely, 213002020232301 is an apocalyptic number.
It is an amenable number.
13002020232301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002020232301 is an equidigital number, since it uses as much as digits as its factorization.
13002020232301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13002020232301 its reverse (10323202020031), we get a palindrome (23325222252332).
The spelling of 13002020232301 in words is "thirteen trillion, two billion, twenty million, two hundred thirty-two thousand, three hundred one".
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