Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1101111100101000110 |
3 | 110102121022222001220220 |
4 | 1321011303233211012 |
5 | 4112240133223024 |
6 | 135421440205210 |
7 | 12252010362411 |
oct | 1710563574506 |
9 | 412538861826 |
10 | 130020211014 |
11 | 50161023a51 |
12 | 21247609806 |
13 | c351130005 |
14 | 641604ab78 |
15 | 35aea06e79 |
hex | 1e45cef946 |
130020211014 has 8 divisors (see below), whose sum is σ = 260040422040. Its totient is φ = 43340070336.
The previous prime is 130020211007. The next prime is 130020211051. The reversal of 130020211014 is 410112020031.
It is a sphenic number, since it is the product of 3 distinct primes.
130020211014 is an admirable number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 130020210984 and 130020211002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10835017579 + ... + 10835017590.
It is an arithmetic number, because the mean of its divisors is an integer number (32505052755).
Almost surely, 2130020211014 is an apocalyptic number.
130020211014 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130020211014 is a wasteful number, since it uses less digits than its factorization.
130020211014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21670035174.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 130020211014 its reverse (410112020031), we get a palindrome (540132231045).
The spelling of 130020211014 in words is "one hundred thirty billion, twenty million, two hundred eleven thousand, fourteen".
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