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1300203000011 = 1403179266183
BaseRepresentation
bin10010111010111010001…
…000110101000011001011
311121022001101022220220002
4102322322020311003023
5132300303432000021
62433145514353215
7162636146102216
oct22727210650313
94538041286802
101300203000011
1146145a7740a3
1218bba342b80b
13957bb1920a6
1446d0450c77d
1523c4bb7350b
hex12eba2350cb

1300203000011 has 4 divisors (see below), whose sum is σ = 1300212406512. Its totient is φ = 1300193593512.

The previous prime is 1300202999971. The next prime is 1300203000043. The reversal of 1300203000011 is 1100003020031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300203000011 - 210 = 1300202998987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300202999956 and 1300203000001.

It is not an unprimeable number, because it can be changed into a prime (1300203002011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4492775 + ... + 4773408.

It is an arithmetic number, because the mean of its divisors is an integer number (325053101628).

Almost surely, 21300203000011 is an apocalyptic number.

1300203000011 is a deficient number, since it is larger than the sum of its proper divisors (9406501).

1300203000011 is an equidigital number, since it uses as much as digits as its factorization.

1300203000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9406500.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1300203000011 its reverse (1100003020031), we get a palindrome (2400206020042).

The spelling of 1300203000011 in words is "one trillion, three hundred billion, two hundred three million, eleven", and thus it is an aban number.

Divisors: 1 140317 9266183 1300203000011