Base | Representation |
---|---|
bin | 1011110100110100011000… |
… | …0110111111000001100100 |
3 | 1201000222112200100010102122 |
4 | 2331031012012333001210 |
5 | 3201011140303203444 |
6 | 43353020012525112 |
7 | 2511236504354216 |
oct | 275150606770144 |
9 | 51028480303378 |
10 | 13002042241124 |
11 | 4163153978782 |
12 | 155ba71780798 |
13 | 734119b02411 |
14 | 32d4333585b6 |
15 | 17832dae04ee |
hex | bd3461bf064 |
13002042241124 has 12 divisors (see below), whose sum is σ = 22799172270000. Its totient is φ = 6487993021128.
The previous prime is 13002042241099. The next prime is 13002042241163. The reversal of 13002042241124 is 42114224020031.
13002042241124 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13002042241093 and 13002042241102.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3257022614 + ... + 3257026605.
It is an arithmetic number, because the mean of its divisors is an integer number (1899931022500).
Almost surely, 213002042241124 is an apocalyptic number.
It is an amenable number.
13002042241124 is a deficient number, since it is larger than the sum of its proper divisors (9797130028876).
13002042241124 is a wasteful number, since it uses less digits than its factorization.
13002042241124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6514049722 (or 6514049720 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 26.
Adding to 13002042241124 its reverse (42114224020031), we get a palindrome (55116266261155).
The spelling of 13002042241124 in words is "thirteen trillion, two billion, forty-two million, two hundred forty-one thousand, one hundred twenty-four".
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