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13002042241124 = 224996514049219
BaseRepresentation
bin1011110100110100011000…
…0110111111000001100100
31201000222112200100010102122
42331031012012333001210
53201011140303203444
643353020012525112
72511236504354216
oct275150606770144
951028480303378
1013002042241124
114163153978782
12155ba71780798
13734119b02411
1432d4333585b6
1517832dae04ee
hexbd3461bf064

13002042241124 has 12 divisors (see below), whose sum is σ = 22799172270000. Its totient is φ = 6487993021128.

The previous prime is 13002042241099. The next prime is 13002042241163. The reversal of 13002042241124 is 42114224020031.

13002042241124 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13002042241093 and 13002042241102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3257022614 + ... + 3257026605.

It is an arithmetic number, because the mean of its divisors is an integer number (1899931022500).

Almost surely, 213002042241124 is an apocalyptic number.

It is an amenable number.

13002042241124 is a deficient number, since it is larger than the sum of its proper divisors (9797130028876).

13002042241124 is a wasteful number, since it uses less digits than its factorization.

13002042241124 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6514049722 (or 6514049720 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 13002042241124 its reverse (42114224020031), we get a palindrome (55116266261155).

The spelling of 13002042241124 in words is "thirteen trillion, two billion, forty-two million, two hundred forty-one thousand, one hundred twenty-four".

Divisors: 1 2 4 499 998 1996 6514049219 13028098438 26056196876 3250510560281 6501021120562 13002042241124