Base | Representation |
---|---|
bin | 1011110100110100011000… |
… | …0110111111000010001011 |
3 | 1201000222112200100010111002 |
4 | 2331031012012333002023 |
5 | 3201011140303204123 |
6 | 43353020012525215 |
7 | 2511236504354303 |
oct | 275150606770213 |
9 | 51028480303432 |
10 | 13002042241163 |
11 | 4163153978808 |
12 | 155ba7178080b |
13 | 734119b02441 |
14 | 32d433358603 |
15 | 17832dae0528 |
hex | bd3461bf08b |
13002042241163 has 2 divisors, whose sum is σ = 13002042241164. Its totient is φ = 13002042241162.
The previous prime is 13002042241099. The next prime is 13002042241189. The reversal of 13002042241163 is 36114224020031.
It is a strong prime.
It is an emirp because it is prime and its reverse (36114224020031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13002042241163 - 26 = 13002042241099 is a prime.
It is not a weakly prime, because it can be changed into another prime (13002042246163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501021120581 + 6501021120582.
It is an arithmetic number, because the mean of its divisors is an integer number (6501021120582).
Almost surely, 213002042241163 is an apocalyptic number.
13002042241163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002042241163 is an equidigital number, since it uses as much as digits as its factorization.
13002042241163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13002042241163 its reverse (36114224020031), we get a palindrome (49116266261194).
The spelling of 13002042241163 in words is "thirteen trillion, two billion, forty-two million, two hundred forty-one thousand, one hundred sixty-three".
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