Base | Representation |
---|---|
bin | 1011110100110100100110… |
… | …0011010101000100101101 |
3 | 1201000222200201000201222201 |
4 | 2331031021203111010231 |
5 | 3201011300100044432 |
6 | 43353025434541501 |
7 | 2511241105340431 |
oct | 275151143250455 |
9 | 51028621021881 |
10 | 13002100003117 |
11 | 4163183540165 |
12 | 155ba88b97891 |
13 | 734128a77804 |
14 | 32d43acb29c1 |
15 | 178333beeee7 |
hex | bd3498d512d |
13002100003117 has 2 divisors, whose sum is σ = 13002100003118. Its totient is φ = 13002100003116.
The previous prime is 13002100003091. The next prime is 13002100003171. The reversal of 13002100003117 is 71130000120031.
13002100003117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (13002100003171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10328420453796 + 2673679549321 = 3213786^2 + 1635139^2 .
It is a cyclic number.
It is not a de Polignac number, because 13002100003117 - 27 = 13002100002989 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13002100003094 and 13002100003103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002100003177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501050001558 + 6501050001559.
It is an arithmetic number, because the mean of its divisors is an integer number (6501050001559).
Almost surely, 213002100003117 is an apocalyptic number.
It is an amenable number.
13002100003117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002100003117 is an equidigital number, since it uses as much as digits as its factorization.
13002100003117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 13002100003117 its reverse (71130000120031), we get a palindrome (84132100123148).
The spelling of 13002100003117 in words is "thirteen trillion, two billion, one hundred million, three thousand, one hundred seventeen".
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