Base | Representation |
---|---|
bin | 10010111010111010100… |
… | …100110011000111100011 |
3 | 11121022001220010102200002 |
4 | 102322322210303013203 |
5 | 132300312321112011 |
6 | 2433150335450215 |
7 | 162636265320524 |
oct | 22727244630743 |
9 | 4538056112602 |
10 | 1300210332131 |
11 | 4614639218a7 |
12 | 18bba598696b |
13 | 957bc85b519 |
14 | 46d0549a84b |
15 | 23c4c620c3b |
hex | 12eba9331e3 |
1300210332131 has 4 divisors (see below), whose sum is σ = 1345045171200. Its totient is φ = 1255375493064.
The previous prime is 1300210332089. The next prime is 1300210332139. The reversal of 1300210332131 is 1312330120031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1300210332131 - 218 = 1300210069987 is a prime.
It is a super-2 number, since 2×13002103321312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300210332139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22417419491 + ... + 22417419548.
It is an arithmetic number, because the mean of its divisors is an integer number (336261292800).
Almost surely, 21300210332131 is an apocalyptic number.
1300210332131 is a deficient number, since it is larger than the sum of its proper divisors (44834839069).
1300210332131 is an equidigital number, since it uses as much as digits as its factorization.
1300210332131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44834839068.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1300210332131 its reverse (1312330120031), we get a palindrome (2612540452162).
The spelling of 1300210332131 in words is "one trillion, three hundred billion, two hundred ten million, three hundred thirty-two thousand, one hundred thirty-one".
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