Base | Representation |
---|---|
bin | 11101100100000011100110… |
… | …010000010001011100110101 |
3 | 122001100220012220212022200011 |
4 | 131210003212100101130311 |
5 | 114020231214412304343 |
6 | 1140310512535020221 |
7 | 36246500250265423 |
oct | 3544034620213465 |
9 | 561326186768604 |
10 | 130021113009973 |
11 | 3847970a7180a9 |
12 | 126bab6780a671 |
13 | 5771c277173b3 |
14 | 24170ac20c113 |
15 | 1007232dba29d |
hex | 7640e6411735 |
130021113009973 has 2 divisors, whose sum is σ = 130021113009974. Its totient is φ = 130021113009972.
The previous prime is 130021113009967. The next prime is 130021113010031. The reversal of 130021113009973 is 379900311120031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84110487565329 + 45910625444644 = 9171177^2 + 6775738^2 .
It is a cyclic number.
It is not a de Polignac number, because 130021113009973 - 221 = 130021110912821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130021113009373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010556504986 + 65010556504987.
It is an arithmetic number, because the mean of its divisors is an integer number (65010556504987).
Almost surely, 2130021113009973 is an apocalyptic number.
It is an amenable number.
130021113009973 is a deficient number, since it is larger than the sum of its proper divisors (1).
130021113009973 is an equidigital number, since it uses as much as digits as its factorization.
130021113009973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30618, while the sum is 40.
The spelling of 130021113009973 in words is "one hundred thirty trillion, twenty-one billion, one hundred thirteen million, nine thousand, nine hundred seventy-three".
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