130021244124441 has 4 divisors (see below), whose sum is σ = 173361658832592. Its totient is φ = 86680829416292.

The previous prime is 130021244124433. The next prime is 130021244124463. The reversal of 130021244124441 is 144421442120031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130021244124441 - 2³ = 130021244124433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130021244124491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21670207354071 + ... + 21670207354076.

It is an arithmetic number, because the mean of its divisors is an integer number (43340414708148).

Almost surely, 2^{130021244124441} is an apocalyptic number.

It is an amenable number.

130021244124441 is a deficient number, since it is larger than the sum of its proper divisors (43340414708151).

130021244124441 is an equidigital number, since it uses as much as digits as its factorization.

130021244124441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43340414708150.

The product of its (nonzero) digits is 24576, while the sum is 33.

Adding to 130021244124441 its reverse (144421442120031), we get a palindrome (274442686244472).

The spelling of 130021244124441 in words is "one hundred thirty trillion, twenty-one billion, two hundred forty-four million, one hundred twenty-four thousand, four hundred forty-one".