Base | Representation |
---|---|
bin | 10010111010111010101… |
… | …101001011110011011111 |
3 | 11121022002001021010010102 |
4 | 102322322231023303133 |
5 | 132300313401433044 |
6 | 2433150454531315 |
7 | 162636323104466 |
oct | 22727255136337 |
9 | 4538061233112 |
10 | 1300212530399 |
11 | 461465093452 |
12 | 18bba6666b3b |
13 | 957c014ac83 |
14 | 46d058ad9dd |
15 | 23c4c90724e |
hex | 12ebab4bcdf |
1300212530399 has 2 divisors, whose sum is σ = 1300212530400. Its totient is φ = 1300212530398.
The previous prime is 1300212530311. The next prime is 1300212530413. The reversal of 1300212530399 is 9930352120031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300212530399 - 220 = 1300211481823 is a prime.
It is a super-3 number, since 3×13002125303993 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300212530899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650106265199 + 650106265200.
It is an arithmetic number, because the mean of its divisors is an integer number (650106265200).
Almost surely, 21300212530399 is an apocalyptic number.
1300212530399 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300212530399 is an equidigital number, since it uses as much as digits as its factorization.
1300212530399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 38.
The spelling of 1300212530399 in words is "one trillion, three hundred billion, two hundred twelve million, five hundred thirty thousand, three hundred ninety-nine".
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