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1300213105 = 5367708563
BaseRepresentation
bin100110101111111…
…1010110101110001
310100121120200001221
41031133322311301
510130323304410
6333004025041
744135425522
oct11537726561
93317520057
101300213105
11607a33394
12303532181
131794b0c89
14c4978849
15792334da
hex4d7fad71

1300213105 has 8 divisors (see below), whose sum is σ = 1564509312. Its totient is φ = 1037334768.

The previous prime is 1300213099. The next prime is 1300213127. The reversal of 1300213105 is 5013120031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300213105 - 217 = 1300082033 is a prime.

It is a super-4 number, since 4×13002131054 (a number of 38 digits) contains 4444 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 352447 + ... + 356116.

It is an arithmetic number, because the mean of its divisors is an integer number (195563664).

Almost surely, 21300213105 is an apocalyptic number.

It is an amenable number.

1300213105 is a deficient number, since it is larger than the sum of its proper divisors (264296207).

1300213105 is an equidigital number, since it uses as much as digits as its factorization.

1300213105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 708935.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 1300213105 is about 36058.4678681721. The cubic root of 1300213105 is about 1091.4525160285.

Adding to 1300213105 its reverse (5013120031), we get a palindrome (6313333136).

The spelling of 1300213105 in words is "one billion, three hundred million, two hundred thirteen thousand, one hundred five".

Divisors: 1 5 367 1835 708563 3542815 260042621 1300213105