Base | Representation |
---|---|
bin | 11000001101111110… |
… | …01111011011011011 |
3 | 1020120010211022201120 |
4 | 30012333033123123 |
5 | 203112022042301 |
6 | 5550105020323 |
7 | 640130252523 |
oct | 140677173333 |
9 | 36503738646 |
10 | 13002143451 |
11 | 5572409900 |
12 | 262a4846a3 |
13 | 12c297250b |
14 | 8b4b66683 |
15 | 511726e36 |
hex | 306fcf6db |
13002143451 has 48 divisors (see below), whose sum is σ = 19417063680. Its totient is φ = 7731662400.
The previous prime is 13002143449. The next prime is 13002143461. The reversal of 13002143451 is 15434120031.
It is a happy number.
It is not a de Polignac number, because 13002143451 - 21 = 13002143449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13002143461) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5900916 + ... + 5903118.
It is an arithmetic number, because the mean of its divisors is an integer number (404522160).
Almost surely, 213002143451 is an apocalyptic number.
13002143451 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13002143451 is a deficient number, since it is larger than the sum of its proper divisors (6414920229).
13002143451 is a wasteful number, since it uses less digits than its factorization.
13002143451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2528 (or 2517 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 13002143451 its reverse (15434120031), we get a palindrome (28436263482).
The spelling of 13002143451 in words is "thirteen billion, two million, one hundred forty-three thousand, four hundred fifty-one".
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