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130022030228999 is a prime number
BaseRepresentation
bin11101100100000100011100…
…111011001011111000000111
3122001100222120211202212122012
4131210010130323023320013
5114020240104214311444
61140311143542124435
736246532055441366
oct3544043473137007
9561328524685565
10130022030228999
113847a040440357
12126bb182a2071b
13577204275c44c
142417157d6b7dd
151007288698b9e
hex76411cecbe07

130022030228999 has 2 divisors, whose sum is σ = 130022030229000. Its totient is φ = 130022030228998.

The previous prime is 130022030228983. The next prime is 130022030229037. The reversal of 130022030228999 is 999822030220031.

It is a weak prime.

It is an emirp because it is prime and its reverse (999822030220031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130022030228999 - 24 = 130022030228983 is a prime.

It is a super-3 number, since 3×1300220302289993 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130022030228399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011015114499 + 65011015114500.

It is an arithmetic number, because the mean of its divisors is an integer number (65011015114500).

Almost surely, 2130022030228999 is an apocalyptic number.

130022030228999 is a deficient number, since it is larger than the sum of its proper divisors (1).

130022030228999 is an equidigital number, since it uses as much as digits as its factorization.

130022030228999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 130022030228999 in words is "one hundred thirty trillion, twenty-two billion, thirty million, two hundred twenty-eight thousand, nine hundred ninety-nine".