Base | Representation |
---|---|
bin | 1011110100110101000000… |
… | …1011111001001001101011 |
3 | 1201000222222110110012112112 |
4 | 2331031100023321021223 |
5 | 3201012012043044242 |
6 | 43353044452232535 |
7 | 2511243626343122 |
oct | 275152013711153 |
9 | 51028873405475 |
10 | 13002211299947 |
11 | 4163230348111 |
12 | 155baba30b74b |
13 | 734145b4521c |
14 | 32d44b9a4ab9 |
15 | 17833d886c82 |
hex | bd3502f926b |
13002211299947 has 2 divisors, whose sum is σ = 13002211299948. Its totient is φ = 13002211299946.
The previous prime is 13002211299943. The next prime is 13002211300027. The reversal of 13002211299947 is 74999211220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13002211299947 - 22 = 13002211299943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13002211299895 and 13002211299904.
It is not a weakly prime, because it can be changed into another prime (13002211299943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501105649973 + 6501105649974.
It is an arithmetic number, because the mean of its divisors is an integer number (6501105649974).
Almost surely, 213002211299947 is an apocalyptic number.
13002211299947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002211299947 is an equidigital number, since it uses as much as digits as its factorization.
13002211299947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 489888, while the sum is 50.
The spelling of 13002211299947 in words is "thirteen trillion, two billion, two hundred eleven million, two hundred ninety-nine thousand, nine hundred forty-seven".
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