Base | Representation |
---|---|
bin | 11101100100000100100010… |
… | …111001000000001010101010 |
3 | 122001100222211211010000201212 |
4 | 131210010202321000022222 |
5 | 114020240310330220132 |
6 | 1140311201515313122 |
7 | 36246534412263122 |
oct | 3544044271001252 |
9 | 561328754100655 |
10 | 130022130320042 |
11 | 3847a091994224 |
12 | 126bb1b044b7a2 |
13 | 577205a40550c |
14 | 2417167383c82 |
15 | 100729236a5b2 |
hex | 764122e402aa |
130022130320042 has 8 divisors (see below), whose sum is σ = 195120302764800. Its totient is φ = 64982029398444.
The previous prime is 130022130320023. The next prime is 130022130320081. The reversal of 130022130320042 is 240023031220031.
130022130320042 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1300221303200422 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14517875192 + ... + 14517884147.
It is an arithmetic number, because the mean of its divisors is an integer number (24390037845600).
Almost surely, 2130022130320042 is an apocalyptic number.
130022130320042 is a deficient number, since it is larger than the sum of its proper divisors (65098172444758).
130022130320042 is a wasteful number, since it uses less digits than its factorization.
130022130320042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29035761580.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130022130320042 its reverse (240023031220031), we get a palindrome (370045161540073).
The spelling of 130022130320042 in words is "one hundred thirty trillion, twenty-two billion, one hundred thirty million, three hundred twenty thousand, forty-two".
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