Base | Representation |
---|---|
bin | 10010111010111011010… |
… | …001110011101101001111 |
3 | 11121022002201022212201002 |
4 | 102322323101303231033 |
5 | 132300323331143043 |
6 | 2433151440410515 |
7 | 162636500521604 |
oct | 22727321635517 |
9 | 4538081285632 |
10 | 1300222131023 |
11 | 46146a550552 |
12 | 18bba9916a3b |
13 | 957c212cb0a |
14 | 46d06c8c6ab |
15 | 23c4d6a1bb8 |
hex | 12ebb473b4f |
1300222131023 has 16 divisors (see below), whose sum is σ = 1399173048000. Its totient is φ = 1205213349120.
The previous prime is 1300222130863. The next prime is 1300222131127. The reversal of 1300222131023 is 3201312220031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300222131023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1300222130986 and 1300222131004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300222131323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4486388 + ... + 4767401.
It is an arithmetic number, because the mean of its divisors is an integer number (87448315500).
Almost surely, 21300222131023 is an apocalyptic number.
1300222131023 is a deficient number, since it is larger than the sum of its proper divisors (98950916977).
1300222131023 is a wasteful number, since it uses less digits than its factorization.
1300222131023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9254002.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1300222131023 its reverse (3201312220031), we get a palindrome (4501534351054).
The spelling of 1300222131023 in words is "one trillion, three hundred billion, two hundred twenty-two million, one hundred thirty-one thousand, twenty-three".
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