Base | Representation |
---|---|
bin | 1011110100110101010110… |
… | …1110101010110010001111 |
3 | 1201001000012221110012200021 |
4 | 2331031111232222302033 |
5 | 3201012204400132343 |
6 | 43353102013443011 |
7 | 2511246136011565 |
oct | 275152556526217 |
9 | 51030187405607 |
10 | 13002304302223 |
11 | 416327889a0a5 |
12 | 155bb254a0467 |
13 | 73415c1a8862 |
14 | 32d45a093a35 |
15 | 178346b080ed |
hex | bd355baac8f |
13002304302223 has 2 divisors, whose sum is σ = 13002304302224. Its totient is φ = 13002304302222.
The previous prime is 13002304302191. The next prime is 13002304302241. The reversal of 13002304302223 is 32220340320031.
It is a strong prime.
It is an emirp because it is prime and its reverse (32220340320031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13002304302223 - 25 = 13002304302191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002301302223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501152151111 + 6501152151112.
It is an arithmetic number, because the mean of its divisors is an integer number (6501152151112).
Almost surely, 213002304302223 is an apocalyptic number.
13002304302223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002304302223 is an equidigital number, since it uses as much as digits as its factorization.
13002304302223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13002304302223 its reverse (32220340320031), we get a palindrome (45222644622254).
The spelling of 13002304302223 in words is "thirteen trillion, two billion, three hundred four million, three hundred two thousand, two hundred twenty-three".
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