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1300231133301 = 3433410377767
BaseRepresentation
bin10010111010111011110…
…100001001100001110101
311121022010100021020111210
4102322323310021201311
5132300333132231201
62433152401352033
7162636640164402
oct22727364114165
94538110236453
101300231133301
1146147463a051
1218bbb0938619
13957c3c624c9
1446d081532a9
1523c4e37e1d6
hex12ebbd09875

1300231133301 has 4 divisors (see below), whose sum is σ = 1733641511072. Its totient is φ = 866820755532.

The previous prime is 1300231133231. The next prime is 1300231133323. The reversal of 1300231133301 is 1033311320031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1300231133301 - 223 = 1300222744693 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300231133351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216705188881 + ... + 216705188886.

It is an arithmetic number, because the mean of its divisors is an integer number (433410377768).

Almost surely, 21300231133301 is an apocalyptic number.

It is an amenable number.

1300231133301 is a deficient number, since it is larger than the sum of its proper divisors (433410377771).

1300231133301 is an equidigital number, since it uses as much as digits as its factorization.

1300231133301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433410377770.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 1300231133301 its reverse (1033311320031), we get a palindrome (2333542453332).

The spelling of 1300231133301 in words is "one trillion, three hundred billion, two hundred thirty-one million, one hundred thirty-three thousand, three hundred one".

Divisors: 1 3 433410377767 1300231133301