Base | Representation |
---|---|
bin | 11101100100000101100011… |
… | …010111011010010001000101 |
3 | 122001101002122012112202002012 |
4 | 131210011203113122101011 |
5 | 114020300014240024333 |
6 | 1140311501120224005 |
7 | 36246603255553361 |
oct | 3544054327322105 |
9 | 561332565482065 |
10 | 130023212033093 |
11 | 3847a597549255 |
12 | 126bb45276b005 |
13 | 57721a0552702 |
14 | 241722acc22a1 |
15 | 10073072dce48 |
hex | 7641635da445 |
130023212033093 has 2 divisors, whose sum is σ = 130023212033094. Its totient is φ = 130023212033092.
The previous prime is 130023212033089. The next prime is 130023212033123. The reversal of 130023212033093 is 390330212320031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116816798145124 + 13206413887969 = 10808182^2 + 3634063^2 .
It is a cyclic number.
It is not a de Polignac number, because 130023212033093 - 22 = 130023212033089 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130023212032093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011606016546 + 65011606016547.
It is an arithmetic number, because the mean of its divisors is an integer number (65011606016547).
Almost surely, 2130023212033093 is an apocalyptic number.
It is an amenable number.
130023212033093 is a deficient number, since it is larger than the sum of its proper divisors (1).
130023212033093 is an equidigital number, since it uses as much as digits as its factorization.
130023212033093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 32.
The spelling of 130023212033093 in words is "one hundred thirty trillion, twenty-three billion, two hundred twelve million, thirty-three thousand, ninety-three".
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