Search a number
-
+
13002321300213 = 37619158157153
BaseRepresentation
bin1011110100110101011010…
…1111100000101011110101
31201001000021010102210112110
42331031112233200223311
53201012223223101323
643353103422041233
72511246433335450
oct275152657405365
951030233383473
1013002321300213
114163287449a23
12155bb2b119219
1373416287a73b
1432d45c43a497
15178348364793
hexbd356be0af5

13002321300213 has 8 divisors (see below), whose sum is σ = 19813061028928. Its totient is φ = 7429897885824.

The previous prime is 13002321300161. The next prime is 13002321300217. The reversal of 13002321300213 is 31200312320031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13002321300213 - 29 = 13002321299701 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 619158157153 = 13002321300213 / (1 + 3 + 0 + 0 + 2 + 3 + 2 + 1 + 3 + 0 + 0 + 2 + 1 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13002321300213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002321300217) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309579078556 + ... + 309579078597.

It is an arithmetic number, because the mean of its divisors is an integer number (2476632628616).

Almost surely, 213002321300213 is an apocalyptic number.

It is an amenable number.

13002321300213 is a deficient number, since it is larger than the sum of its proper divisors (6810739728715).

13002321300213 is an equidigital number, since it uses as much as digits as its factorization.

13002321300213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 619158157163.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13002321300213 its reverse (31200312320031), we get a palindrome (44202633620244).

The spelling of 13002321300213 in words is "thirteen trillion, two billion, three hundred twenty-one million, three hundred thousand, two hundred thirteen".

Divisors: 1 3 7 21 619158157153 1857474471459 4334107100071 13002321300213