Base | Representation |
---|---|
bin | 1011110100110101100010… |
… | …0001010100011011001010 |
3 | 1201001000100012120112100201 |
4 | 2331031120201110123022 |
5 | 3201012303342300120 |
6 | 43353110405322414 |
7 | 2511250245043561 |
oct | 275153041243312 |
9 | 51030305515321 |
10 | 13002351134410 |
11 | 41632a2276890 |
12 | 155bb3910640a |
13 | 734168ac5101 |
14 | 32d4623a4bd8 |
15 | 17834aca940a |
hex | bd3588546ca |
13002351134410 has 16 divisors (see below), whose sum is σ = 25531889500512. Its totient is φ = 4728127685200.
The previous prime is 13002351134407. The next prime is 13002351134413. The reversal of 13002351134410 is 1443115320031.
It is an interprime number because it is at equal distance from previous prime (13002351134407) and next prime (13002351134413).
It is a super-2 number, since 2×130023511344102 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13002351134413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59101595956 + ... + 59101596175.
It is an arithmetic number, because the mean of its divisors is an integer number (1595743093782).
Almost surely, 213002351134410 is an apocalyptic number.
13002351134410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13002351134410 is a deficient number, since it is larger than the sum of its proper divisors (12529538366102).
13002351134410 is a wasteful number, since it uses less digits than its factorization.
13002351134410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118203192149.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13002351134410 its reverse (1443115320031), we get a palindrome (14445466454441).
The spelling of 13002351134410 in words is "thirteen trillion, two billion, three hundred fifty-one million, one hundred thirty-four thousand, four hundred ten".
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