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13002420200402 = 26501210100201
BaseRepresentation
bin1011110100110101110010…
…1000110010001111010010
31201001000112000112110002102
42331031130220302033102
53201012424032403102
643353121313520402
72511252044100263
oct275153450621722
951030460473072
1013002420200402
11416332825a116
12155bb58273102
1373417a1c7769
1432d46b62296a
15178351d9d402
hexbd35ca323d2

13002420200402 has 4 divisors (see below), whose sum is σ = 19503630300606. Its totient is φ = 6501210100200.

The previous prime is 13002420200387. The next prime is 13002420200417. The reversal of 13002420200402 is 20400202420031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13002420200387) and next prime (13002420200417).

It can be written as a sum of positive squares in only one way, i.e., 7593116424721 + 5409303775681 = 2755561^2 + 2325791^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250605050099 + ... + 3250605050102.

Almost surely, 213002420200402 is an apocalyptic number.

13002420200402 is a deficient number, since it is larger than the sum of its proper divisors (6501210100204).

13002420200402 is an equidigital number, since it uses as much as digits as its factorization.

13002420200402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6501210100203.

The product of its (nonzero) digits is 768, while the sum is 20.

Adding to 13002420200402 its reverse (20400202420031), we get a palindrome (33402622620433).

The spelling of 13002420200402 in words is "thirteen trillion, two billion, four hundred twenty million, two hundred thousand, four hundred two".

Divisors: 1 2 6501210100201 13002420200402