Base | Representation |
---|---|
bin | 11101100100000110100000… |
… | …001010101101000010111010 |
3 | 122001101012021022000010201002 |
4 | 131210012200022231002322 |
5 | 114020304111410043224 |
6 | 1140312150240125002 |
7 | 36246640453233311 |
oct | 3544064012550272 |
9 | 561335238003632 |
10 | 130024232112314 |
11 | 3847aa70336931 |
12 | 126bb698306762 |
13 | 57723039a0097 |
14 | 24172c6579278 |
15 | 1007366b389ae |
hex | 7641a02ad0ba |
130024232112314 has 4 divisors (see below), whose sum is σ = 195036348168474. Its totient is φ = 65012116056156.
The previous prime is 130024232112311. The next prime is 130024232112319. The reversal of 130024232112314 is 413211232420031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 129909502906225 + 114729206089 = 11397785^2 + 338717^2 .
It is not an unprimeable number, because it can be changed into a prime (130024232112311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32506058028077 + ... + 32506058028080.
Almost surely, 2130024232112314 is an apocalyptic number.
130024232112314 is a deficient number, since it is larger than the sum of its proper divisors (65012116056160).
130024232112314 is an equidigital number, since it uses as much as digits as its factorization.
130024232112314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65012116056159.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 130024232112314 its reverse (413211232420031), we get a palindrome (543235464532345).
The spelling of 130024232112314 in words is "one hundred thirty trillion, twenty-four billion, two hundred thirty-two million, one hundred twelve thousand, three hundred fourteen".
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