13002440403 has 4 divisors (see below), whose sum is σ = 17336587208. Its totient is φ = 8668293600.

The previous prime is 13002440393. The next prime is 13002440483. The reversal of 13002440403 is 30404420031.

13002440403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30404420031 = 3 ⋅10134806677.

It is not a de Polignac number, because 13002440403 - 2²⁵ = 12968885971 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13002440403.

It is not an unprimeable number, because it can be changed into a prime (13002440483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167073398 + ... + 2167073403.

It is an arithmetic number, because the mean of its divisors is an integer number (4334146802).

Almost surely, 2^13002440403 is an apocalyptic number.

13002440403 is a deficient number, since it is larger than the sum of its proper divisors (4334146805).

13002440403 is an equidigital number, since it uses as much as digits as its factorization.

13002440403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4334146804.

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 13002440403 its reverse (30404420031), we get a palindrome (43406860434).

The spelling of 13002440403 in words is "thirteen billion, two million, four hundred forty thousand, four hundred three".