Base | Representation |
---|---|
bin | 111100100011000011… |
… | …0110010100101110111 |
3 | 110102121200100202010112 |
4 | 1321012012302211313 |
5 | 4112242423012322 |
6 | 135422135213235 |
7 | 12252100666442 |
oct | 1710606624567 |
9 | 412550322115 |
10 | 130025204087 |
11 | 50163924359 |
12 | 2124921721b |
13 | c35218a8ac |
14 | 641698a659 |
15 | 35b01915e2 |
hex | 1e461b2977 |
130025204087 has 2 divisors, whose sum is σ = 130025204088. Its totient is φ = 130025204086.
The previous prime is 130025204063. The next prime is 130025204131. The reversal of 130025204087 is 780402520031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130025204087 - 224 = 130008426871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130025204017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012602043 + 65012602044.
It is an arithmetic number, because the mean of its divisors is an integer number (65012602044).
Almost surely, 2130025204087 is an apocalyptic number.
130025204087 is a deficient number, since it is larger than the sum of its proper divisors (1).
130025204087 is an equidigital number, since it uses as much as digits as its factorization.
130025204087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
The spelling of 130025204087 in words is "one hundred thirty billion, twenty-five million, two hundred four thousand, eighty-seven".
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