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130025431 is a prime number
BaseRepresentation
bin1111100000000…
…00011111010111
3100001122222100201
413300000133113
5231241303211
620522521331
73136124614
oct760003727
9301588321
10130025431
116743a038
1237666247
1320c27233
14133a950b
15b6360c1
hex7c007d7

130025431 has 2 divisors, whose sum is σ = 130025432. Its totient is φ = 130025430.

The previous prime is 130025407. The next prime is 130025477. The reversal of 130025431 is 134520031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130025431 - 219 = 129501143 is a prime.

It is a super-2 number, since 2×1300254312 = 33813225413471522, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130025399 and 130025408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130025131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012715 + 65012716.

It is an arithmetic number, because the mean of its divisors is an integer number (65012716).

Almost surely, 2130025431 is an apocalyptic number.

130025431 is a deficient number, since it is larger than the sum of its proper divisors (1).

130025431 is an equidigital number, since it uses as much as digits as its factorization.

130025431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 130025431 is about 11402.8694195803. The cubic root of 130025431 is about 506.6127326497.

Adding to 130025431 its reverse (134520031), we get a palindrome (264545462).

The spelling of 130025431 in words is "one hundred thirty million, twenty-five thousand, four hundred thirty-one".