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130025431903 is a prime number
BaseRepresentation
bin111100100011000011…
…1101010001101011111
3110102121200210022122011
41321012013222031133
54112243002310103
6135422144132051
712252102635563
oct1710607521537
9412550708564
10130025431903
1150163a6a534
1221249307027
13c35223a4b3
146416a096a3
1535b01d8d6d
hex1e461ea35f

130025431903 has 2 divisors, whose sum is σ = 130025431904. Its totient is φ = 130025431902.

The previous prime is 130025431847. The next prime is 130025431937. The reversal of 130025431903 is 309134520031.

It is a strong prime.

It is an emirp because it is prime and its reverse (309134520031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130025431903 - 29 = 130025431391 is a prime.

It is a super-2 number, since 2×1300254319032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130025411903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012715951 + 65012715952.

It is an arithmetic number, because the mean of its divisors is an integer number (65012715952).

Almost surely, 2130025431903 is an apocalyptic number.

130025431903 is a deficient number, since it is larger than the sum of its proper divisors (1).

130025431903 is an equidigital number, since it uses as much as digits as its factorization.

130025431903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 130025431903 its reverse (309134520031), we get a palindrome (439159951934).

The spelling of 130025431903 in words is "one hundred thirty billion, twenty-five million, four hundred thirty-one thousand, nine hundred three".