Base | Representation |
---|---|
bin | 111100100011000011… |
… | …1101010001101011111 |
3 | 110102121200210022122011 |
4 | 1321012013222031133 |
5 | 4112243002310103 |
6 | 135422144132051 |
7 | 12252102635563 |
oct | 1710607521537 |
9 | 412550708564 |
10 | 130025431903 |
11 | 50163a6a534 |
12 | 21249307027 |
13 | c35223a4b3 |
14 | 6416a096a3 |
15 | 35b01d8d6d |
hex | 1e461ea35f |
130025431903 has 2 divisors, whose sum is σ = 130025431904. Its totient is φ = 130025431902.
The previous prime is 130025431847. The next prime is 130025431937. The reversal of 130025431903 is 309134520031.
It is a strong prime.
It is an emirp because it is prime and its reverse (309134520031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130025431903 - 29 = 130025431391 is a prime.
It is a super-2 number, since 2×1300254319032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130025411903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012715951 + 65012715952.
It is an arithmetic number, because the mean of its divisors is an integer number (65012715952).
Almost surely, 2130025431903 is an apocalyptic number.
130025431903 is a deficient number, since it is larger than the sum of its proper divisors (1).
130025431903 is an equidigital number, since it uses as much as digits as its factorization.
130025431903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 130025431903 its reverse (309134520031), we get a palindrome (439159951934).
The spelling of 130025431903 in words is "one hundred thirty billion, twenty-five million, four hundred thirty-one thousand, nine hundred three".
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