Base | Representation |
---|---|
bin | 1011110100110110010001… |
… | …1011111010000001101011 |
3 | 1201001000212010201220020021 |
4 | 2331031210123322001223 |
5 | 3201013211031322110 |
6 | 43353142310141311 |
7 | 2511255223165153 |
oct | 275154433720153 |
9 | 51030763656207 |
10 | 13002551042155 |
11 | 41633950a64a4 |
12 | 155bb94051837 |
13 | 73419b34940c |
14 | 32d480b61763 |
15 | 17835d5e62da |
hex | bd3646fa06b |
13002551042155 has 4 divisors (see below), whose sum is σ = 15603061250592. Its totient is φ = 10402040833720.
The previous prime is 13002551042147. The next prime is 13002551042171. The reversal of 13002551042155 is 55124015520031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13002551042155 - 23 = 13002551042147 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13002551042155.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1300255104211 + ... + 1300255104220.
It is an arithmetic number, because the mean of its divisors is an integer number (3900765312648).
Almost surely, 213002551042155 is an apocalyptic number.
13002551042155 is a deficient number, since it is larger than the sum of its proper divisors (2600510208437).
13002551042155 is an equidigital number, since it uses as much as digits as its factorization.
13002551042155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2600510208436.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 13002551042155 its reverse (55124015520031), we get a palindrome (68126566562186).
The spelling of 13002551042155 in words is "thirteen trillion, two billion, five hundred fifty-one million, forty-two thousand, one hundred fifty-five".
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