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1300285857143 = 71394631509971
BaseRepresentation
bin10010111010111111000…
…100111001110101110111
311121022021011020111111202
4102322333010321311313
5132300441134412033
62433202034323115
7162641203265210
oct22727704716567
94538234214452
101300285857143
114614a2516969
1219000712949b
13958023b2a90
1446d1151a407
1523c5408d8e8
hex12ebf139d77

1300285857143 has 16 divisors (see below), whose sum is σ = 1600522000896. Its totient is φ = 1028688202080.

The previous prime is 1300285857127. The next prime is 1300285857163. The reversal of 1300285857143 is 3417585820031.

It is not a de Polignac number, because 1300285857143 - 24 = 1300285857127 is a prime.

It is a super-2 number, since 2×13002858571432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300285857163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106148 + ... + 1616118.

It is an arithmetic number, because the mean of its divisors is an integer number (100032625056).

Almost surely, 21300285857143 is an apocalyptic number.

1300285857143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1300285857143 is a deficient number, since it is larger than the sum of its proper divisors (300236143753).

1300285857143 is a wasteful number, since it uses less digits than its factorization.

1300285857143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1519454.

The product of its (nonzero) digits is 806400, while the sum is 47.

The spelling of 1300285857143 in words is "one trillion, three hundred billion, two hundred eighty-five million, eight hundred fifty-seven thousand, one hundred forty-three".

Divisors: 1 7 13 91 9463 66241 123019 861133 1509971 10569797 19629623 137407361 14288855573 100021989011 185755122449 1300285857143