Base | Representation |
---|---|
bin | 10010111010111111000… |
… | …100111001110101110111 |
3 | 11121022021011020111111202 |
4 | 102322333010321311313 |
5 | 132300441134412033 |
6 | 2433202034323115 |
7 | 162641203265210 |
oct | 22727704716567 |
9 | 4538234214452 |
10 | 1300285857143 |
11 | 4614a2516969 |
12 | 19000712949b |
13 | 958023b2a90 |
14 | 46d1151a407 |
15 | 23c5408d8e8 |
hex | 12ebf139d77 |
1300285857143 has 16 divisors (see below), whose sum is σ = 1600522000896. Its totient is φ = 1028688202080.
The previous prime is 1300285857127. The next prime is 1300285857163. The reversal of 1300285857143 is 3417585820031.
It is not a de Polignac number, because 1300285857143 - 24 = 1300285857127 is a prime.
It is a super-2 number, since 2×13002858571432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300285857163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106148 + ... + 1616118.
It is an arithmetic number, because the mean of its divisors is an integer number (100032625056).
Almost surely, 21300285857143 is an apocalyptic number.
1300285857143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1300285857143 is a deficient number, since it is larger than the sum of its proper divisors (300236143753).
1300285857143 is a wasteful number, since it uses less digits than its factorization.
1300285857143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1519454.
The product of its (nonzero) digits is 806400, while the sum is 47.
The spelling of 1300285857143 in words is "one trillion, three hundred billion, two hundred eighty-five million, eight hundred fifty-seven thousand, one hundred forty-three".
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