Search a number
-
+
130028716053833 is a prime number
BaseRepresentation
bin11101100100001010101011…
…011011100101010101001001
3122001101121211210022222010012
4131210022223123211111021
5114020342302302210313
61140314211214401305
736250156541142152
oct3544125333452511
9561347753288105
10130028716053833
1138481961409523
1212700529b00235
13577286994350c
1424175cdca4929
15100752a603da8
hex7642ab6e5549

130028716053833 has 2 divisors, whose sum is σ = 130028716053834. Its totient is φ = 130028716053832.

The previous prime is 130028716053811. The next prime is 130028716053869. The reversal of 130028716053833 is 338350617820031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128282081564224 + 1746634489609 = 11326168^2 + 1321603^2 .

It is an emirp because it is prime and its reverse (338350617820031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130028716053833 - 212 = 130028716049737 is a prime.

It is not a weakly prime, because it can be changed into another prime (130028716053883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65014358026916 + 65014358026917.

It is an arithmetic number, because the mean of its divisors is an integer number (65014358026917).

Almost surely, 2130028716053833 is an apocalyptic number.

It is an amenable number.

130028716053833 is a deficient number, since it is larger than the sum of its proper divisors (1).

130028716053833 is an equidigital number, since it uses as much as digits as its factorization.

130028716053833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 130028716053833 in words is "one hundred thirty trillion, twenty-eight billion, seven hundred sixteen million, fifty-three thousand, eight hundred thirty-three".