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130030011322111 = 433023953751677
BaseRepresentation
bin11101100100001011111000…
…101000101000111011111111
3122001101202012001121102011101
4131210023320220220323333
5114020402430344301421
61140314543524433531
736250233616554415
oct3544137050507377
9561352161542141
10130030011322111
113848246657477a
121270082b8488a7
135772a150b2854
1424176b3d132b5
1510075a41ac191
hex7642f8a28eff

130030011322111 has 4 divisors (see below), whose sum is σ = 133053965073832. Its totient is φ = 127006057570392.

The previous prime is 130030011322093. The next prime is 130030011322147. The reversal of 130030011322111 is 111223110030031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130030011322111 - 211 = 130030011320063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130030011322511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1511976875796 + ... + 1511976875881.

It is an arithmetic number, because the mean of its divisors is an integer number (33263491268458).

Almost surely, 2130030011322111 is an apocalyptic number.

130030011322111 is a deficient number, since it is larger than the sum of its proper divisors (3023953751721).

130030011322111 is an equidigital number, since it uses as much as digits as its factorization.

130030011322111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3023953751720.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 130030011322111 its reverse (111223110030031), we get a palindrome (241253121352142).

The spelling of 130030011322111 in words is "one hundred thirty trillion, thirty billion, eleven million, three hundred twenty-two thousand, one hundred eleven".

Divisors: 1 43 3023953751677 130030011322111