Base | Representation |
---|---|
bin | 11101100100001011111001… |
… | …110011110100110000100010 |
3 | 122001101202020102200202010110 |
4 | 131210023321303310300202 |
5 | 114020403000421000310 |
6 | 1140314545511112150 |
7 | 36250234246232613 |
oct | 3544137163646042 |
9 | 561352212622113 |
10 | 130030031031330 |
11 | 38482476706591 |
12 | 12700836372656 |
13 | 5772a191c3801 |
14 | 24176b67a3c0a |
15 | 10075a5ca1d20 |
hex | 7642f9cf4c22 |
130030031031330 has 16 divisors (see below), whose sum is σ = 312072074475264. Its totient is φ = 34674674941680.
The previous prime is 130030031031317. The next prime is 130030031031349. The reversal of 130030031031330 is 33130130030031.
It is a junction number, because it is equal to n+sod(n) for n = 130030031031297 and 130030031031306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2167167183826 + ... + 2167167183885.
It is an arithmetic number, because the mean of its divisors is an integer number (19504504654704).
Almost surely, 2130030031031330 is an apocalyptic number.
130030031031330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130030031031330 is an abundant number, since it is smaller than the sum of its proper divisors (182042043443934).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130030031031330 is a wasteful number, since it uses less digits than its factorization.
130030031031330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4334334367721.
The product of its (nonzero) digits is 729, while the sum is 21.
Adding to 130030031031330 its reverse (33130130030031), we get a palindrome (163160161061361).
The spelling of 130030031031330 in words is "one hundred thirty trillion, thirty billion, thirty-one million, thirty-one thousand, three hundred thirty".
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